<<@TheOrganicChemistryTutor
says :
Projectile Motion - Free Formula Sheet: https://bit.ly/3ZmmL6r Full Projectile Motion Video: https://bit.ly/3WWnzL4 Physics 1 Final Exam Review: https://www.youtube.com/watch?v=CwkhvFlNFp0 Physics PDF Worksheets: https://www.video-tutor.net/physics.html
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<<@jjeeqq
says :
Add curvature of surface (ball) and place a target on that curvature, then calculate angle to shoot that target with best efficient. This formula doesn't work on curvature.
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<<@KodxQ8
says :
I used to watch these videos for education in high school/university days. But now as a physics teacher, I watch them for fun.
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<<@antoniovivaldi9999
says :
Thank you so much!
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<<@thenomad5652
says :
I was hell confused cause that I studied that slope part long ago now I get know how graphically slope is max at 0
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<<@8Space
says :
For anyone who wants to know how to find the equation for the range: The range will be equal to the initial velocity in the horizontal direction multiplied to the time if there is no drag. R = Vix(t) Now to solve for time, imagine you are thrown vertically and you are deccelerating because of the gravity by for example 9.81 m/s² that means each second you lost 9.81 m/s of velocity. So if you were thrown vertically by 9.81 m/s in 1 second your velocity will become 0 then you will accelerate downward due to gravity until you return to your original position. The time it took you to lose the speed you had upward, will be the same time it will take you to return to the ground. so t = 2(Viy/g) Now R will be equal to = Vix(2)(Viy/g) The horizontal component can be solved using trigonometry. Vix = Vi cos(theta) Viy = Vi sin(theta) So Vix(Viy) = Vi²(sin(theta))(cos(theta)) Now R becomes: = [Vi²•2•(sin(θ)•cos(θ))]/g 2sin(θ)cos(θ) = sin(2θ) from trig angle addition identity: sin(A + B) = sin(A)cos(B) + sin(B)cos(A) sin(2A) = sin(A + A) Now for the final result R = [(Vi)²(sin(2θ))]/g I'm not sure if I explained that well.
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<<@SamDomaloy
says :
WTF??!
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<<@kaiser7637
says :
I looked everywhere but I can't find an explanation as to why the range equation is the way it is. I can't seem to factor it in a way that gets gravity (g) on the bottom
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<<@baconman132
says :
so is this just optimization? been learning that lately, and it feels familiar
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<<@cianconway2540
says :
Is range being v^2sin(2 theta) all over g a given or how do I calculate it if asked to show the max range of a particle in terms of v and theta
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<<@showtimebaby7
says :
SELAM OLSUN
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<<@NotAMimic02
says :
Hi
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<<@redrevyol
says :
You can also use sin(2*theta) = 1 because one is the maximum value for sine.
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<<@TheEngineerBlueprint
says :
One question closer to acing that exam in 22 days. Thank you!
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<<@deltaepsilonphi
says :
The best tutor!
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<<@ALPHIAMONTALES
says :
Wow cool ahhhhhhhhhhhhhh 😏
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<<@NoctisTheopilus
says :
Bro I don't want to launch my Balls!
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<<@sussushi
says :
genuinely, quite literally, the realest munda on the planet
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<<@rcasewst
says :
Did not account for drag
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<<@guidoreuter6032
says :
Assuming the firing occurs on a planet void of atmosphere
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<<@bagda4667
says :
45degree 😂😂😂😂😂😂
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<<@gui-zx3di
says :
9/2v**2 *0?? Is it not wrong to multiply it knowing that this side is 0?
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<<@SarrouTube
says :
Amazing video !! The theory behind the experiment ! Keep uploading !!
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<<@AceAdora
says :
could you make a video about all the set theory proofs and practice problems ? thanks !
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<<@AhShtHereWeeGoAgain
says :
Thanks a lot 😊
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<<@victoryfirst06
says :
Do you plan to make a video about maximum range angle from non-leveled surfaces as well? I would be very interested to see that one.
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<<@ZurerBW
says :
Two days later is my exam and projectile motion is in the syllabusm, What a coincidence
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<<@thatomofolo452
says :
Goat
>>
<<@conspis-gq3ug
says :
when is face reveal
>>
<<@victorpaulsacyabon7664
says :
can you explain the trigonometric identities super hexagon?
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<<@Crissss-b5z
says :
Sir you are good 👍 teacher I speak broken English but I can understand what you say from 🇳🇵
>>
<<@wilkyclergeot9416
says :
The best tutor
>>
<<@learinna425
says :
U make me enjoy learning
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<<@learinna425
says :
Ur voice is so hot
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<<@Josh-x2t5d
says :
best tutor
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<<@coolperson3339
says :
Thanks!
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<<@ryanclovis_2010
says :
Thanks tr
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<<@domstaruc-hw3gi
says :
the best tutor i know!!
>>
<<@AbundanceM234
says :
Thus guy is more legit than my teachers 😢💀
>>
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